`@receiver staticPart: `@arg2 `anyKeywordPart: `@arg1It’s incredibly powerful. But how do you remember all of this?
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* 解题思路：先对nums2用单调栈求每个元素的下一个更大值，存入Map缓存；再遍历nums1直接查Map得结果
「但最近，這些驚喜變得不大令人愉快了，短期內恐怕仍會持續如此。」